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2x*3x=147^2
We move all terms to the left:
2x*3x-(147^2)=0
We add all the numbers together, and all the variables
2x*3x-21609=0
Wy multiply elements
6x^2-21609=0
a = 6; b = 0; c = -21609;
Δ = b2-4ac
Δ = 02-4·6·(-21609)
Δ = 518616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{518616}=\sqrt{86436*6}=\sqrt{86436}*\sqrt{6}=294\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-294\sqrt{6}}{2*6}=\frac{0-294\sqrt{6}}{12} =-\frac{294\sqrt{6}}{12} =-\frac{49\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+294\sqrt{6}}{2*6}=\frac{0+294\sqrt{6}}{12} =\frac{294\sqrt{6}}{12} =\frac{49\sqrt{6}}{2} $
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